Hi everyone!

I am back with Polynomials, as you know we finish our polynomials Unit
and UNIT TEST on Thursday!!

anyway today in class we write a little bit note about what is going to be on the test and the marks of the test

so our test is going to be out off 55
check out what is going to be in our test on Thursday


Part A= Translating

which looks like this

Ex. 9 less than x
they say that nine is less than x
so we took the word less which means
SUBTRACT
so we will write in this way

= X-9

Ex. Twice a number, decreased by 4

so we choose any letters to represent the
number
for example i choose letter N to represent my number
as you know decreased which means SUBTRACT
so we will represent in this way

=2n-4

Part B= Terminology

This terminology is example of ADDITIVE INVERSE which means opposite

This simple

Ex. what is the additive inverse of 3
which means the opposite of 3
which is -3.
Ex. what is the additive inverse of x

which is -x

Part C= Substitution

Let's look at an example using the Substitution method:

Ex. 3x-4y when x=3 and y=-3

So we know that x=3 and y=-3

now we can solve this equation
by putting 3 into the x and
-3 into the y

3x-4y

=3(3)-4(-3)
=9+12
=21 ans
it is simple very easy!

Ex. 2(3x-4y)-3(2x+2y) when x=2 and y=-2
We start with PEDMAS

=6x-8y-6x-6y
=6x-6x-8y-6y
=-14y
=-14(-2)
=28


Part D= Simplification:
.Add,Subtract,Multiply

simplifying is one of my best part

Ex. simplify by combining like terms.

d+d+d+d+p+p+p+d

we collect the like terms then we add them which will give as

=5d+3p

stop there because they are no more like terms
but remember multiplying polynomials can multiply
with any kind of variables.

Ex. (d-5) - (d+3)

so this question is subtracting polynomials
as we know we change the other side to opposite

= (d-5) - (d+3)
= (d-5) + (-d-3) we change the other side
= d-5-d-3 we took off the brackets
= d-d-5-3 we collect the like terms and solve it
= -8 this is what we found!

it is simple if you try more


let see multiply polynomials

Ex. (-2m^3)(m)


(-2m^3)(m)

=-2m^4 we add the exponent thats why i get m^4

Lets try another one

(2x^2)(-3y)

=-12x^2y


Part E= Word Problem
.Algetiles (subtract)
. Perimeter/Area rectangle
.Find missing side given Perimeter
. Creating dimensions

Lets use this question with algetiles

Ex. (-3x+10) - (-10x-8)




lets try another question



so in this rectangle they give as the length
and the width
so if we want to find the perimeter of this rectangle we add the all side.

P=x+x+5x+5x P=2x+10x P=12x

If they told us to find the are of the
rectangle we multiply

A=L*W

A= x(5x)
A= 5x^2


ANYWAY THIS IS WHAT SHOULD STUDY FOR YOUR TEST

Labels: Polynomials, yassin

Hi everyone!!! Today in class we did some nice activities such as the TEST review and jeopardy games and it was great for us who were in the class.

This are some of the activities we did in class.

Check out with this question

1) Add/ subtract

(5x²-3x+5)+(2x²-7x-10)=

5x²-3x+5+2x²-7x-10

=7x²-10x-5

it is simple if you try more!!

The Perimeter of the following triangle is 16x-12. Find the expression of BC.

(6x-3) +(3x-4)

=6x-3+3x-4

=9x-7



P=16x-12

Now we subtract (9x-7) from the Perimeter of the triangle.

Lets try It!!



(16x-12)-(9x-7)

as we know we subracting we change the other side in opposite.
We took off the brackets

=16x-12-9x+7

=16x-9x-12+7

=7x-5

REMEMBER THURSDAY TEST

FOR MORE PRACTICE CHECK OUT THIS

Labels: pelo, Polynomials

I was picked to be the scribe for today in Math
Today in math we learned about Pedmas and Substitution

-When you're given a substitution question, first expand and simplify the polynomial as much as possible and then substitute at the very end.

Ex 1. x=5 and y = -2

2(2x + 3y) + 3(-3x + 2x) - (2x - 2y)
P :2(2x + 3y) + 3(-x) - (2x - 2y) : We only add like terms
E : No exponents
D : No division
M : 4x + 6y + -3x - 2x - 2y
A : -x + 8y
S : No subtraction

Now lets substitute : -x + 8y
= -(5) + 8(-2) : x becomes 5, y becomes -2
= -5 + (-16)
= -21

Other than taking notes on pedmas and Substitution, we got a new worksheet called "Polynomials using substitution" which is worksheet on the stuff we learned that class.

Hello class! I changed my scribe a little this time. Hopefully you find it more understandable and easier to go through (:




One thing i forgot to mention on my slide is HOMEWORK! complete pg. 63 1, 3, 5, 7, 9, 11, 13, 15, 19, 21 a & b (:

Labels: aLisa, Daily Blog

Hi everybody Im Michael and Im the scribe for today

ok so today in class Ms Nicholson gave us some notes to copy about substitution and evaluating an expression.
here are the notes that she gave us:
*in polynomials if a number is substituted into an expression for the variable, then the expression has a value. This is called "evaluating an expression".

after copying the notes she gave us, she gave us a problem to solve about the notes that we just copied.
Here's the problem: evaluate the following polynomial expression if b = 3
-4b2 + 8b - 5
to solve this problem we have to follow two steps.
step 1 : substitute 3 in for every b. which will give us:
-4(3)2+ 8(3) - 5
step 2 : use PEDMAS to find the value of the expression:
= -4(3)2 + 8(3) - 5
= -4(9) + 8(3) - 5
= -36 + 24 - 5
= -12 - 5
= -17
so the value of this expression is -17,
-17 is the answer for this problem.

after doing that Ms Nicholson asked us to group up so that we can pick the top 3 gifts that we are going to donate to the children in Africa, and the top 3 gifts that we have picked are, warm blankets, mosquito nets and seeds of a coconut tree.

and that ends my scribe for today...... hope that you understand it.

Labels: michael